, .
log ( , log) . . . :
z log(7*3^x) = log(5 * 2^x) z:log 7 + (log3)x = log5 + (log2)x:log5-log7 = (log3 -log2) x
x = (log5-log7) / (log3 - log2) = [rules of logarythms] = log(5/7) / log(3/2) = log(5/7 in base 3/2) z.
: . :z (3/2)^x = 5/7
x = log(5/7 in base 3/2) z.
.
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' ' -12/05/11 -05/07/12.
Medieval Ages
Journey to The Past, - Agaisnt the Jammuza
, , Martin's Story.
.
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~ 2015
I will eat you all! Num Num Num Num!
STM= system to manage
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' ' -12/05/11 -05/07/12.
Medieval Ages
Journey to The Past, - Agaisnt the Jammuza
, , Martin's Story.
.
: ( , )
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